How do i make a program in c language that encrypt vowel in a string?

example when i input hello the output will be h*ll0

How do i make a program in c language that encrypt vowel in a string?
#include %26lt;stdio.h%26gt;


#include %26lt;string.h%26gt;





void mask_vowels(char* chars, size_t len)


{


size_t i;


size_t j;


char source_chars[] = "aeiou";


char replace_chars[] = "@*!0%";





for (i=0; i%26lt;len; i++)


{


for (j=0; j%26lt;strlen(source_chars); j++)


{


if (chars[i] == source_chars[j])


{


chars[i] = replace_chars[j];


break;


}


}


}


}





int main(int argc, char* argv[])


{


// This is just to test that it works, try to replace the chars in the first command line argument and print out the results


if (argc %26gt; 1)


mask_vowels(argv[1], strlen(argv[1]));





printf("%s\n", argv[1]);


}








Just make source_chars and replace_chars are the same size if you change them.
Reply:Create a function that will accept a string and return another string. The function will examine the passed string byte-by-byte. A case structure can echo non-vowels to the return string and replace vowels in whatever manner you want - either a 1-for-1 replacement with the same character replacing the same vowel each time or a random replacement. When the entire passed string has been processed, return the modified string.